Optimal. Leaf size=124 \[ \frac {2 (d x)^{5/2} \left (a+b \sin ^{-1}(c x)\right )}{5 d}+\frac {12 b d^{3/2} F\left (\left .\sin ^{-1}\left (\frac {\sqrt {c} \sqrt {d x}}{\sqrt {d}}\right )\right |-1\right )}{25 c^{5/2}}-\frac {12 b d^{3/2} E\left (\left .\sin ^{-1}\left (\frac {\sqrt {c} \sqrt {d x}}{\sqrt {d}}\right )\right |-1\right )}{25 c^{5/2}}+\frac {4 b \sqrt {1-c^2 x^2} (d x)^{3/2}}{25 c} \]
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Rubi [A] time = 0.10, antiderivative size = 124, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.438, Rules used = {4627, 321, 329, 307, 221, 1199, 424} \[ \frac {2 (d x)^{5/2} \left (a+b \sin ^{-1}(c x)\right )}{5 d}+\frac {12 b d^{3/2} F\left (\left .\sin ^{-1}\left (\frac {\sqrt {c} \sqrt {d x}}{\sqrt {d}}\right )\right |-1\right )}{25 c^{5/2}}-\frac {12 b d^{3/2} E\left (\left .\sin ^{-1}\left (\frac {\sqrt {c} \sqrt {d x}}{\sqrt {d}}\right )\right |-1\right )}{25 c^{5/2}}+\frac {4 b \sqrt {1-c^2 x^2} (d x)^{3/2}}{25 c} \]
Antiderivative was successfully verified.
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Rule 221
Rule 307
Rule 321
Rule 329
Rule 424
Rule 1199
Rule 4627
Rubi steps
\begin {align*} \int (d x)^{3/2} \left (a+b \sin ^{-1}(c x)\right ) \, dx &=\frac {2 (d x)^{5/2} \left (a+b \sin ^{-1}(c x)\right )}{5 d}-\frac {(2 b c) \int \frac {(d x)^{5/2}}{\sqrt {1-c^2 x^2}} \, dx}{5 d}\\ &=\frac {4 b (d x)^{3/2} \sqrt {1-c^2 x^2}}{25 c}+\frac {2 (d x)^{5/2} \left (a+b \sin ^{-1}(c x)\right )}{5 d}-\frac {(6 b d) \int \frac {\sqrt {d x}}{\sqrt {1-c^2 x^2}} \, dx}{25 c}\\ &=\frac {4 b (d x)^{3/2} \sqrt {1-c^2 x^2}}{25 c}+\frac {2 (d x)^{5/2} \left (a+b \sin ^{-1}(c x)\right )}{5 d}-\frac {(12 b) \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {1-\frac {c^2 x^4}{d^2}}} \, dx,x,\sqrt {d x}\right )}{25 c}\\ &=\frac {4 b (d x)^{3/2} \sqrt {1-c^2 x^2}}{25 c}+\frac {2 (d x)^{5/2} \left (a+b \sin ^{-1}(c x)\right )}{5 d}+\frac {(12 b d) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-\frac {c^2 x^4}{d^2}}} \, dx,x,\sqrt {d x}\right )}{25 c^2}-\frac {(12 b d) \operatorname {Subst}\left (\int \frac {1+\frac {c x^2}{d}}{\sqrt {1-\frac {c^2 x^4}{d^2}}} \, dx,x,\sqrt {d x}\right )}{25 c^2}\\ &=\frac {4 b (d x)^{3/2} \sqrt {1-c^2 x^2}}{25 c}+\frac {2 (d x)^{5/2} \left (a+b \sin ^{-1}(c x)\right )}{5 d}+\frac {12 b d^{3/2} F\left (\left .\sin ^{-1}\left (\frac {\sqrt {c} \sqrt {d x}}{\sqrt {d}}\right )\right |-1\right )}{25 c^{5/2}}-\frac {(12 b d) \operatorname {Subst}\left (\int \frac {\sqrt {1+\frac {c x^2}{d}}}{\sqrt {1-\frac {c x^2}{d}}} \, dx,x,\sqrt {d x}\right )}{25 c^2}\\ &=\frac {4 b (d x)^{3/2} \sqrt {1-c^2 x^2}}{25 c}+\frac {2 (d x)^{5/2} \left (a+b \sin ^{-1}(c x)\right )}{5 d}-\frac {12 b d^{3/2} E\left (\left .\sin ^{-1}\left (\frac {\sqrt {c} \sqrt {d x}}{\sqrt {d}}\right )\right |-1\right )}{25 c^{5/2}}+\frac {12 b d^{3/2} F\left (\left .\sin ^{-1}\left (\frac {\sqrt {c} \sqrt {d x}}{\sqrt {d}}\right )\right |-1\right )}{25 c^{5/2}}\\ \end {align*}
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Mathematica [C] time = 0.03, size = 66, normalized size = 0.53 \[ \frac {2 (d x)^{3/2} \left (5 a c x-2 b \, _2F_1\left (\frac {1}{2},\frac {3}{4};\frac {7}{4};c^2 x^2\right )+2 b \sqrt {1-c^2 x^2}+5 b c x \sin ^{-1}(c x)\right )}{25 c} \]
Antiderivative was successfully verified.
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fricas [F] time = 2.00, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (b d x \arcsin \left (c x\right ) + a d x\right )} \sqrt {d x}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (d x\right )^{\frac {3}{2}} {\left (b \arcsin \left (c x\right ) + a\right )}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 138, normalized size = 1.11 \[ \frac {\frac {2 \left (d x \right )^{\frac {5}{2}} a}{5}+2 b \left (\frac {\left (d x \right )^{\frac {5}{2}} \arcsin \left (c x \right )}{5}-\frac {2 c \left (-\frac {d^{2} \left (d x \right )^{\frac {3}{2}} \sqrt {-c^{2} x^{2}+1}}{5 c^{2}}-\frac {3 d^{3} \sqrt {-c x +1}\, \sqrt {c x +1}\, \left (\EllipticF \left (\sqrt {d x}\, \sqrt {\frac {c}{d}}, i\right )-\EllipticE \left (\sqrt {d x}\, \sqrt {\frac {c}{d}}, i\right )\right )}{5 c^{3} \sqrt {\frac {c}{d}}\, \sqrt {-c^{2} x^{2}+1}}\right )}{5 d}\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {2}{5} \, b d^{\frac {3}{2}} x^{\frac {5}{2}} \arctan \left (c x, \sqrt {c x + 1} \sqrt {-c x + 1}\right ) + \frac {2}{5} \, {\left (a d x^{\frac {5}{2}} + 5 \, b c d \int \frac {\sqrt {c x + 1} \sqrt {-c x + 1} x^{\frac {5}{2}}}{5 \, {\left (c^{2} x^{2} - 1\right )}}\,{d x}\right )} \sqrt {d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \left (a+b\,\mathrm {asin}\left (c\,x\right )\right )\,{\left (d\,x\right )}^{3/2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 17.70, size = 82, normalized size = 0.66 \[ a \left (\begin {cases} 0 & \text {for}\: d = 0 \\\frac {2 \left (d x\right )^{\frac {5}{2}}}{5 d} & \text {otherwise} \end {cases}\right ) - b c \left (\begin {cases} 0 & \text {for}\: d = 0 \\\frac {d^{\frac {3}{2}} x^{\frac {7}{2}} \Gamma \left (\frac {7}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{2}, \frac {7}{4} \\ \frac {11}{4} \end {matrix}\middle | {c^{2} x^{2} e^{2 i \pi }} \right )}}{5 \Gamma \left (\frac {11}{4}\right )} & \text {otherwise} \end {cases}\right ) + b \left (\begin {cases} 0 & \text {for}\: d = 0 \\\frac {2 \left (d x\right )^{\frac {5}{2}}}{5 d} & \text {otherwise} \end {cases}\right ) \operatorname {asin}{\left (c x \right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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